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+# CrackMeOne
+
+## Steps
+
+- Launch x32dbg and open the exe
+
+- Run up until `EntryPoint`
+
+- Open the strings view
+
+- Find
+  
+  > Congratulations, you found the secret password
+  
+  This must be our code path on success. Double click to find it in the assembly view.
+
+- Insert some breakpoints before and play around with entering password (anything is fine) and stepping through code, observing registers etc.
+
+- Observe that there is a loop iterating through bytes at `*eax` and `*ecx` and comparing them.
+  eax points to our entered password, ecx points to `j5%9lk`.
+
+- Clearly we are checking for equality between these two strings, thus this is the password.
+
+- If we complete the loop, we jump straight to the `test eax, eax` that gates the success path. If we don't, we jump a few instrs before, where `eax` is set to a value that is always non-zero (thus we take the branch, which we don't want to).
+  `eax` will be zero in the success path due to the final equality check being performed on the null-byte string terminator.## Solution
+
+
+
+## Solution
+
+Password: `j5%9lk`.
+
+