# CrackMeOne

## Steps

- Launch x32dbg and open the exe

- Run up until `EntryPoint`

- Open the strings view

- Find
  
  > Congratulations, you found the secret password
  
  This must be our code path on success. Double click to find it in the assembly view.

- Insert some breakpoints before and play around with entering password (anything is fine) and stepping through code, observing registers etc.

- Observe that there is a loop iterating through bytes at `*eax` and `*ecx` and comparing them.
  eax points to our entered password, ecx points to `j5%9lk`.

- Clearly we are checking for equality between these two strings, thus this is the password.

- If we complete the loop, we jump straight to the `test eax, eax` that gates the success path. If we don't, we jump a few instrs before, where `eax` is set to a value that is always non-zero (thus we take the branch, which we don't want to).
  `eax` will be zero in the success path due to the final equality check being performed on the null-byte string terminator.## Solution



## Solution

Password: `j5%9lk`.